Web1 Feb 2024 · Method 2. An alternate method to solve the problem is by using the general formula to find the sum of the first N natural numbers. The same can be implemented with PL/SQL. The formula for finding the sum of first N natural numbers is ( N ∗ … Web10 Oct 2024 · Given a number N, the task is to find the sum of digits of a number at even and odd places. Examples: Input: N = 54873 Output: Sum odd = 16 Sum even = 11 Input: N = 457892 Output: Sum odd = 20 Sum even = 15 Recommended: Please try your approach on {IDE} first, before moving on to the solution. Approach:
Sum the digits of a number in mysql - Stack Overflow
Web2 Jul 2024 · Approach is to initialize a num with 1 and sum with 0 and keep incrementing num by 2 and sum by num until num <= N. -- display all odd number from 1 to n DECLARE -- declare variable num num NUMBER (3) := 1; sum1 NUMBER (4) := 0; BEGIN WHILE num <= 5 LOOP -- display odd number dbms_output.Put_line (num); -- the sum of all odd numbers Web20 May 2024 · SQL> set serveroutput on SQL> declare 2 i integer; 3 s integer; 4 begin 5 s:=0; 6 for i in 1..10 loop 7 s:=s+i; 8 end loop; 9 dbms_output.put_line ('Sum = ' s); 10 end; 11 / Sum = 55 PL/SQL procedure successfully completed. Rate this: Share this: WhatsApp Facebook Loading... Posted in Oracle / SQL Tagged SQL SET SERVEROUTPUT ON: – rtx 2080 ti waterblock
Sum Of Two Numbers in PL/SQL - GeeksforGeeks
Web5 Sep 2024 · One thing to note in this solution is that you must add as many additions (each with it's own % and /) as you might have digits on the supplied values. Also, if you want to … Web22 Jan 2024 · DECLARE number NUMBER(3) := 1; sumvar NUMBER(4) := 0; BEGIN dbms_output.Put_line('The odd numbers are : '); WHILE num <= 7 LOOP dbms_output.Put_line(number); sumvar := sumvar+num; num := num + 2; END LOOP; dbms_output.Put_line('Sum of odd numbers is ' sum1); END; Output The odd numbers … Web6 Aug 2024 · Input − n = 31415. Output − 8. Explanation − first digit = 3 , last digit = 5. Sum = 8. To, solve this problem, we will extract the first and last digit to number n. And the print … rtx 2080 ti used